标题：请教Qms、Qes、Qts各自的物理意义是什么!!!!
此主题相关图片如下：等效电路.jpg
扬声器在无限大障板上的低频等效电路(阻抗型,全部转换为力学等效元件)
Mms=Mmd+2Mmr
高频时，必须加进去考虑。还有辐射阻。
而对于Ｑｍｓ是指的是机械Ｑ值．
而对于Ｑｅｓ指的是电气Ｑ值了．
总体讲的就是Ｑ值也就是衡量一个ＳＰＥＡＫＥＲ的品质因数了．
而对于Ｑｔｓ就是Ｑｍｓ Ｑｅｓ成并联关系了．
楼上的话多了。
这几个TS参数我也糊涂了，还向初哥请教过，我的参考资料都是王老的两本书设计手册和工艺手册，
就是这两本书里面的计算方法都不一样，特别是工艺手册，上面的公式推导下来相互之间都不能等式
还望有高人指点一下，或者推荐一下其它的书。
"Q" is one of those dimensionless numbers that causes no small amount of consternation amongst those who don't understand what it means, as well as among those that THINK they do! However, the principle behind Q, when used in the context of loudspeakers, is VERY simple. It is simply the ratio between energy storing and energy dissipative mechanisms at resonance. In electrical terms, it is the ratio of the reactance to the resistance.
A high Q indicates that for the amount of energy stored in a resonant system, the mechanisms that dissipate that energy are small. So a high-Q system will tend to have a resonance that decays slowly, because the amount of resistance available to dissipate the energy is small compared to the amount of energy stored. A low-Q system will tend to dampen the resonant motion quickly, because the energy is dissipated quickly and removed from the resonant system.
There are primarily 2 energy dissipating mechanisms available in a loudspeaker driver: mechanical and electrical (there is another, acoustical, but it is VERY small when compared to the other mechanisms). The mechanical dissipative mechanisms are primarily the frictional losses in the driver's suspension, and, to a lesser extent, acoustic absorption. There are, essentially, two electrical mechanisms for energy dissipation: the DC resistance to the voice coil and the output resistance of the amplifier. In almost all cases, the DC resistance of the voice coil completely dominates.
These two mechanisms, mechanical and electrical, determine, respectively, the mechanical Q (Qms) and the electrical Q(Qes) of the loudspeaker driver. Their parallel combination determines the total Q (Qts) of the loudspeaker driver." Amen.
When we mount a loudspeaker driver onto a baffle system we also have to take into account the Q of the baffle system to arrive at the total system Q. To work out the total Q of the driver and baffle system you simply multiply the baffle system Q with the total Q of the loudspeaker driver. Closed boxes store energy that interacts with the loudspeaker driver in complex ways, especially in vented enclosures. Boxes themselves also have resonances. Normally a high-Q closed box is combined with low-Q loudspeaker driver to give a desirable total system Q. But when we mount a loudspeaker driver on an open baffle this situation is reversed. An open baffle stores no energy and has a low-Q of 0.2 and Carver chose to use a high-Q woofer with a total Q of 3+ to arrive at a desirable total system Q.
Carver's high-Q woofer was also chosen for another good reason to do with mounting a woofer on an open baffle. As we decrease in frequency or increase in wavelength, the system initially behaves as an infinite baffle. When the wavelengths are long enough to be a quarter of the baffle dimensions, the waves begin to cancel each other around the edges of the dipole baffle. The wave travels out to the edge (1/4) and back to the opposite side of the vibrating speaker cone, where it is exactly out of phase and cancels out. Quarter wave cancellation on an open baffle is a first order phenomenon – the roll-off occurs at 6dB per octave. When we reach the free-air resonance point of the high-Q woofer we add to this the second-order sub-resonance fall-off of the high-Q woofer to end up with a third-order or 18db per octave fall-off below the free-air resonance point of the high-Q woofer (this makes a good rumble filter in the Carver case).
In loudspeaker literature we can look at the family of curves for the frequency response of a loudspeaker driver on an infinite baffle as we decrease the frequency. Starting with the rolled-off curve when Q=0.5 (critically damped), then the Butterworth graph with Q=0.71 (maximally flat), then a little ripple at Q=1, then clearly a bumped-up graph at Q=1.4. When the Q is higher than any you can usually find in loudspeaker driver catalogues you start to get boosting above the resonance point of the loudspeaker driver, and a sufficiently high-Q will result in a slope of about 6dB per octave above the free-air resonance point of the loudspeaker driver. This increase of 6dB per octave of the high-Q loudspeaker driver can be used to counteract the 6dB per octave quarter wave cancellation to give a flat frequency response right down to the free-air resonant frequency of the loudspeaker driver. This is a much more elegant solution to the problem of quarter wave cancellation on an open baffle to that used by Celestion, etc of using a conventional low-Q woofer with electronic equalization since it does not involve additional amplifier power and the necessity of electronic equalization equipment.High-Q woofers are relatively easy to design/make. Both ways of overcoming quarter wave cancellation on a baffle entail the use of long throw woofers for the safe operation of the woofer.
Qms 力学智商
Qes 电学智商
Qts 总智商
啥叫智商
智商高,反应快吧
太聪明,太笨多不好,
多大的智商,住在多大房子里,有无没窗,最好?
智商正常的人呢,那就是普通人了,住的都是有窗的正常房子.
这个世界上正常人多,那么也就说建设的正常房子多.
至于智商多少住多大的房子倒是没明确规定,因为跟度量,抗压能力有关.
上面的帖子也进行了一些有趣的探讨.
由此得出如下结论:
一个家庭的成败(通常指一个男人的成败),往往取决于男人的能力以及他身后站的什么样的女人!!
这与现实当中我们经常讲的一个成功的男人,身后必有一个女人这个道理是吻合的.
具体论证过程请参照国明大师如下论点:
1. Qm高但Qe低
2. Qm低但Qe高
3. QmQe两者皆高
4. QmQe两者皆低
试对上述四种情况对其重放声音特性进行定性分析.
这道题目,如果用抽象模型去像, 大家很容易想到头昏, 搞糊涂了,就算电声高手也未必能答得出, 但你现在使用我做的QmQe阴阳类比.
则问题变得极易解决:
1. Qm高Qe低----说明男人很强, 但女人控制力强(理财能力强).这样的组合很好. 扬声器方面----声音又好听, 控制力有好, 理想的单体.
2. Qm低Qe高----说明男人很衰(没钱没力),女人控制力不强(乱花钱),这样的家庭叫败家. 扬声器方面----低音既出不来, 振动还止不住.
没见过这么差的单元了.
3. QmQe都高----说明男人很强会赚钱, 但女人也很会花钱,不懂理财, 有意思吧, 这样的组合看实际情况, 如果男人赚的钱够女人花,
OK没问题, 如果男人赚的钱不够女人糟的, 那日久仍然会出问题. 用在扬声器方面----要根据具体情况具体讨论, 分析
孰强孰弱, 孰为主孰为从,孰占问题的主动方面
4. QmQe都低----说明男人衰,赚不到钱, 但女人也扣门, 手头控制得紧(生活, 没办法呀) 这样的家庭组合呢, 日子过得平平淡淡如流水,
在扬声器方面,声音听起来就是---干巴巴的毫无个性, 平平淡淡的基本上没什么得失吧.