标题：求教！这样的圆柱形空间会对声音产生什么样的影响？
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长度40mm 直径 10mm.
求教
他会在什么频段产生共振，如何计算。
谢谢各位大侠。
为啥木人理偶
spk正面出来的频响象锯齿.
大约在4kHz及其倍数频率上有谐振
有空可看看Sakai的文章
Acoustic Field in an Enclosure and Its Effect on Sound-Pressure Responses of a Loudspeaker
The acoustic field in a loudspeaker enclosure with rigid walls and its effect on the sound-pressure responses are investigated by applying the finite-element method to the acoustic cavity of the enclosure. Sound-pressure responses are calculated by simulating the loudspeaker system with an electromechanical equivalent circuit. These responses are then evaluated in terms of location, semiapex angle, radius, and mass of the loudspeaker diaphragm.
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谢谢 各位 另一端封闭的
请教各位大侠：计算方式。
大约在4kHz及其倍数频率上有谐振
有空可看看Sakai的文章
Acoustic Field in an Enclosure and Its Effect on Sound-Pressure Responses of a Loudspeaker
The acoustic field in a loudspeaker enclosure with rigid walls and its effect on the sound-pressure responses are investigated by applying the finite-element method to the acoustic cavity of the enclosure. Sound-pressure responses are calculated by simulating the loudspeaker system with an electromechanical equivalent circuit. These responses are then evaluated in terms of location, semiapex angle, radius, and mass of the loudspeaker diaphragm.
Click to purchase paper or login as an AES member. If your company or school subscribes to the E-Library then switch to the institutional version. If you are not an AES member and would like to subscribe to the E-Library then Join the AES!
老大，这是一本书 还是一篇文章啊
小弟英文不太好。有没有中文译本
有点意思！方形箱体的驻波计算很熟悉了。圆柱形箱体的驻波，是否只有长度一维方向需要考虑呢？
按照“音响师声学基础”，90页的内容，可以把这个看成一个管乐器，而且是一端封闭的。
它的所有可能激发的驻波频率为：
f=(2n-1)*c/4
其中，n=1,2,3,......
L为管的尺度（m),C为声速。
那么，计算的结果就是：212.5, 637.5, ......Hz了。
不知道这样做对吗？